Codecov Report

Merging #96 (2067695) into master (c2e5e21) will decrease coverage by 0.44%.
The diff coverage is 44.44%.

@@            Coverage Diff             @@
##           master      #96      +/-   ##
==========================================
- Coverage   83.31%   82.86%   -0.45%     
==========================================
  Files          40       40              
  Lines         809      817       +8     
==========================================
+ Hits          674      677       +3     
- Misses        135      140       +5     

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I revent these changes with #101
It seems that's not the right solution, yet.

e.g.:

With your PR:

Before the PR:

(We also see here that the 4it is in both cases a little confusing. Maybe you address this in #98 )

Think the problem is that we have two kind of "main/sub tasks", e.g.:

• Subdivide a number of "jobs" into chunks and process these chunks parallelized. The one from the screenshot. It's the example tasks here:

  django-huey-monitor/huey_monitor_tests/test_app/tasks.py

  Lines 86 to 111 in 35feb4d

  	def parallel_sub_task(task, parent_task_id, item_chunk, **info_kwargs):
  	"""
  	Useless example: Just calculate the SHA256 hash from all files
  	"""
  	# Save relationship between the main and sub tasks:
  	TaskModel.objects.set_parent_task(
  	main_task_id=parent_task_id,
  	sub_task_id=task.id
  	)
  	total_items = len(item_chunk)
  	# Init progress information of this sub task:
  	process_info = ProcessInfo(
  	task, total=total_items, parent_task_id=parent_task_id, **info_kwargs
  	)
  	for entry in item_chunk:
  	# ...do something with >entry< ...
  	logger.info('process %s', entry)
  	time.sleep(1)
  	# Update sub and main task progress:
  	process_info.update(n=1)
  	logger.info('Chunk finish: %s', process_info)

• Group different sub-task with different "total counts" (Your use-case, mention in Status of Parent task not depending on progress vs.total #91 )

Think the second one are not as an example in the DEMO project. We should add this and look if all changes are a good ideas for both cases!